(k-7)-(2k^2-3k)=

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Solution for (k-7)-(2k^2-3k)= equation:


Simplifying
(k + -7) + -1(2k2 + -3k) = 0

Reorder the terms:
(-7 + k) + -1(2k2 + -3k) = 0

Remove parenthesis around (-7 + k)
-7 + k + -1(2k2 + -3k) = 0

Reorder the terms:
-7 + k + -1(-3k + 2k2) = 0
-7 + k + (-3k * -1 + 2k2 * -1) = 0
-7 + k + (3k + -2k2) = 0

Combine like terms: k + 3k = 4k
-7 + 4k + -2k2 = 0

Solving
-7 + 4k + -2k2 = 0

Solving for variable 'k'.

Begin completing the square.  Divide all terms by
-2 the coefficient of the squared term: 

Divide each side by '-2'.
3.5 + -2k + k2 = 0

Move the constant term to the right:

Add '-3.5' to each side of the equation.
3.5 + -2k + -3.5 + k2 = 0 + -3.5

Reorder the terms:
3.5 + -3.5 + -2k + k2 = 0 + -3.5

Combine like terms: 3.5 + -3.5 = 0.0
0.0 + -2k + k2 = 0 + -3.5
-2k + k2 = 0 + -3.5

Combine like terms: 0 + -3.5 = -3.5
-2k + k2 = -3.5

The k term is -2k.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2k + 1 + k2 = -3.5 + 1

Reorder the terms:
1 + -2k + k2 = -3.5 + 1

Combine like terms: -3.5 + 1 = -2.5
1 + -2k + k2 = -2.5

Factor a perfect square on the left side:
(k + -1)(k + -1) = -2.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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